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You have a router called CK , and there five separate paths to a given destination. The
EIGRP metrics for these five paths are:
TK
Path 1: 1500
Path 2: 1500
Path 3: 2000
Path 4: 4000
Path 5: 4000
Assuming that variance 3 is configured on Router CK , which of the above paths are in
TK's routing table to get to the given destination?A. path 1, 2, and 4B. path 1, 2, and 3C. path 1, 2, and 5D. path 1, 2, 4, and 5
Ans: B
Explanation: Variance allows the router to include routes with a metric smaller than variance
times the minimum metric route to that destination. In this scenario variance is equal to 3. All
paths with a value less than 4500 (1500*3) would be included in the routing table.
According to the book "CCNP Cisco Networking Academy Program: Semester Five
companion Guide
Advance Routing" by Mark McGregor, Vito Amato(year 2001), Chapter 6 page
252:
"EIGRP will maintain up to four routes per destination. These routes can be
of equal or unequal cost.
Variance command enables unequal-cost load balancing...."
So according to the above paragraph, a maximum of 4 routes (equal or unequal or combination
of both)
per destination are to be included in the routing table.
Ans e is wrong. d. seems to be most appropriate but still d. should not be path 1,2,4,5 but it
should be path 1,2,3,4 because path 3 is less in cost compare with path 4 or 5, so should it be
selected before path 4 or path 5 got selected?
Q2
You are a network administrator on a Cisco router that's running EIGRP. You want to
aggregate a route; which of the following commands below would you enter to configure
the summary route you need?A. ip auto-summary as-number address maskB. ip summary-address as-number address maskC. ip auto-summary eigrp as-number address maskD. ip summary-route eigrp as-number address maskE. ip summary-address eigrp as-number address mask
Ans: E
Explanation: The ip summary-address eigrp command is used to configure a summary
aggregate address for a specified interface.
Syntax: ip summary-address eigrp autonomous-system-number address mask
Incorrect Anss
A, C, D: No such command.
B: We must specify the appropriate protocol with the eigrp keyword.
Q3
You are reviewing the configuration files on a 256kpps HDLC interface, and you see some
interesting data:
interface serial 0/0
bandwidth 56
ip bandwidth-percent eigrp 1 200
From the command output above, how many kbps of bandwidth is allocated for EIGRP
traffic?A. 56 kbpsB. 112 kbpsC. 128 kbpsD. 256 kbps
Ans: B
Explanation:
The bandwidth-percent command tells EIGRP what percentage of the configured bandwidth it
may use. The default is 50 percent. Since the bandwidth command is also used to set the routing
protocol metric, it may be set to a particular value for policy reasons. The bandwidth-percent
command can have values greater than 100 if the bandwidth is configured artificially low due to
such policy reasons.
Reference:
http://www.cisco.com/en/US/tech/ CK3 65/ CK2 07/technologies_tech_note09186a0080094063.shtml
Q4
Behold the configuration of a 256kbps HDLC interface.
interface serial 0/0
bandwidth 56
ip bandwidth-percent eigrp 1 200
From the information attained in the above example; how much bandwidth did this system
administrator allocate for EIGRP traffic?A. 56 kbpsB. 112 kbpsC. 128 kbpsD. 200 kbpsE. 256 kbps
Ans: B
Explanation: The ip bandwidth-percent eigrp command is used to configure the percentage of
bandwidth that may be used by Enhanced IGRP (EIGRP) on an interface. In this scenario 200%
of 56 kbps is chosen. This is 112 kbps.
Note: Syntax
ip bandwidth-percent eigrp as-number percent
The percent can be higher than 100%.
Reference: Cisco, Enhanced IGRP Commands
Q5
Exhibit:
All of the routers in the above network segment are configured with EIGRP. If by mishap
CertKing 2 and CertKing 3 were to fail, how would CertKing 1 react?A. CertKing 1 will automatically route packets via CertKing 4 to the CertKing Main Office
Network.B. CertKing 1 will place the route via CertKing 4 into the hold down state.C. CertKing 1 will go into the active state for all routers.D. CertKing 1 will go into the active state for the route to CertKing Main Office Network.
Ans: A
Explanation: First it checks the topology table for an alternate route then it sends a query to
neighboring routers for other routes to the destination.
Q6
You are the network engineer at CertKing . The CertKing network has five paths from
Router CK1 to a given destination. The local EIGRP metric on Router CK1 for these paths
are as follows:
local
Path 1: 1500
Path 2: 1500
Path 3: 2000
Path 4: 4000
Path 5: 4000
Variance 3 is configured on Router CK1 . Which paths would be included in Router CK1 's
routing table?A. path 1, 2, and 4B. path 1, 2, and 3C. path 1, 2, and 5D. path 1, 2, 4 and 5E. path 1, 2, 3, 4, and 5
Ans: E
Explanation:
If the variance number is higher than the default 1, the EIGRP process multiples the best (lowest)
cost or metric value for a path by the number stated as the variance multiplier. All paths to the
same destination that have metrics within this new range are now included in load balancing. Per
the question this means: 1500*3=4500. All available options are within 1500-4500.
Source: Self-Study CCNP BSCI Exam Certification Guide Third Edition P.485, Topic: Load
Balancing in EIGRP
Q7
Which one of the following commands would configure EIGRP for IP on your Cisco
router?A. ip eigrp routingB. router eigrp process-idC. ip eigrp autonomous-system-numberD. router eigrp autonomous-system-number
Ans: D
Explanation:
Perform the following steps to configure EIGRP for IP:
Step 1 Enable EIGRP and define the autonomous system.
routerTK(config)#router eigrp autonomous-system-number
Step 2 Indicate which networks are part of the EIGRP autonomous system.
routerTK(config-router)#network network-number
Step 3 Define bandwidth of a link for the purposes of sending routing update traffic on the link.
routerTK(config-if)#bandwidth kilobits
Q8
Exhibit:
variance number
In the EIGRP command sequence above, what is the function of the number variable?A. It acts as a multiplier.B. It defines the limit for how far the metrics can be separated.C. It indicates how many paths can be used for load balancing.D. It indicates how many paths can be used for unequal load balancing.
Ans: A
Explanation: Every routing protocol supports equal cost path load balancing. IGRP and EIGRP
also support unequal cost path load balancing, which is known as variance. The variance
number command instructs the router to include routes with a metric less than or equal to
number times the minimum metric route for that destination. Thus number is used as multiplier,
even though it defines a limit for the metrics, This limit is used for unequal load balancing.
Reference: How Does Unequal Cost Path Load Balancing (Variance) Work in IGRP and
EIGRP?
http://www.cisco.com/warp/public/103/19.html
Incorrect Anss
B: Number does not directly define a limit.
C, D: Number does directly indicate how many paths that can be used.
Q9
Exhibit:
You are the systems administrator of the above EIGRP network and you've elected to shut
down router B's FDDI interface. After you execute the shutdown, which router will become
the feasible successor to network 7 for router A?A. BB. DC. HD. There is no feasible successor
Ans: D
Explanation: Router H will be the successor, and that route will be placed in the Routing table.
Router A detects the link failure between Router B and network 7. It checks the topology table
for a successor. It finds that H is the successor since the advertised distance for H (30) is less
than the feasible distance for B (31).
However, there is no next best route - no feasible successor. The candidate route through D has
an advertised distance (220) that is higher than the feasible distance of the successor route (40).
Note: Successor is a route selected as the primary route to use to reach a destination. Successors
are the entries kept in the routing table.
A feasible successor is a backup route. These routes are selected at the same time the successors
are identified, but they are kept in a topology table,
Incorrect Anss
A: The FDDI interface of B is down.
B: The candidate route through D has an advertised distance (220) that is higher than the feasible
distance of the successor route (40). It cannot be used as a feasible successor.
C: Router H is the successor, not the feasible successor.
Q0
You are the network engineer at CertKing . You want to configure EIGRP to run across a
56 Kbps serial PPP link on the CertKing network. You also want to ensure proper
convergence of EIGRP routes.
What command should you issue on the serial interface?A. bandwidth 56B. bandwidth 56000C. ip bandwidth-percent eigrp 1 56D. ip bandwidth-percent eigrp 1 56000
Ans: A
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